Question

Из города А в 8 часов утра вышел грузовик со скоростью 32 км/час, а в 11 часов дня вслед за ним выехал автобус со скоростью 56 км/час. В какое время и на каком расстоянии от города А автобус догонит грузовик?

Answer 1

1) 56 - 32 = 24часа разница во времени

2) 11- 8 = на 3 часа позже выехал автобус

3) 32 х 3 = 96 км проехал грузовик до того как выехал автобус

4) 96: 4 = 4 час за это время автобус догонит грузовик

5) 11+ 4 = 15 часов в это время автобус догнал грузовик

6) 56 х 4 = 224 км на таком расстоянии от города автобус догонит грузовик

Answer 2

Problem Analysis

We are given that a truck leaves city A at 8:00 AM with a speed of 32 km/h, and a bus leaves city A at 11:00 AM with a speed of 56 km/h. We need to determine at what time and at what distance from city A the bus will catch up to the truck.

Solution

To solve this problem, we can use the formula: time = distance / speed.

Let's assume that the bus catches up to the truck after time 't' hours. During this time, the truck would have traveled a distance of 32t km, and the bus would have traveled a distance of 56t km.

Since the bus catches up to the truck, the distances traveled by both vehicles must be equal. Therefore, we can set up the following equation:

32t = 56t

Simplifying the equation, we get:

56t - 32t = 0 24t = 0 t = 0

This means that the bus catches up to the truck after 0 hours, or immediately. Since the bus leaves city A at 11:00 AM, it catches up to the truck at the same time.

To find the distance at which the bus catches up to the truck, we can substitute the value of 't' into either the distance traveled by the truck or the bus. Let's use the distance traveled by the truck:

Distance = 32t = 32 * 0 = 0 km

Therefore, the bus catches up to the truck at a distance of 0 km from city A.

Answer

The bus catches up to the truck immediately at 11:00 AM and at a distance of 0 km from city A.

Please let me know if you need any further clarification.