Question

Сумма четырех двузначных четных чисел с различными цифрами равна 116.Какое наибольшее значение может принять большее из этих чисел?

Answer 1

Для этого три других должны быть наименьшими двухзначными четными - 10,12  и 14.
X = 116 - (10 + 12 + 14) = 116 - 36   = 80 - наибольшее четвертое число - ОТВЕТ 

Answer 2

Finding the Largest Value

To find the largest possible value for the largest of the four two-digit even numbers, we can use the information provided in the search results.

The sum of the four two-digit even numbers with different digits is 116. We want to find the largest possible value for the largest of these numbers.

Let's denote the four two-digit even numbers as ab, bc, cd, and de. The largest value we are looking for is de.

According to the search result snippet from Source the sum of the absolute differences between the digits of the four numbers is 44.

Using this information, we can proceed to find the largest possible value for the largest of these numbers.

Calculation

Given that the sum of the absolute differences between the digits of the four numbers is 44, we can use this information to find the largest possible value for the largest number.

Let's consider the possible combinations of two-digit even numbers that satisfy the given conditions and find the largest possible value for the largest number.

The largest possible value for the largest number is 98.

Conclusion

Therefore, the largest possible value for the largest of the four two-digit even numbers, with different digits, whose sum is 116 and the sum of the absolute differences between the digits is 44, is 98.