Question

Задача по математика 4 класс часть 2 стр.75 задача 301 от двух пристаней находящихся на расстояниии др. от др. 560км. отправились баржа и катер.Через сколь. часов они встретились если скорость баржи 25 км/ч а скорость катера 45км/ч?

Answer 1

 1) 25+45=70 км/час скорость сближения баржи с катером                                2) 560:70=8 часов  
   Ответ: через 8 часов встретились

Answer 2

Problem Analysis

The problem involves calculating the time it takes for a barge and a motorboat to meet, given their respective speeds and the distance between two piers.

Given Data

- Distance between the piers: 560 km - Speed of the barge: 25 km/h - Speed of the motorboat: 45 km/h

Solution

To solve this problem, we can use the formula: \[ \text{time} = \frac{\text{distance}}{\text{speed}} \]

Calculations

For the barge: \[ \text{time}_\text{barge} = \frac{560}{25} = 22.4 \text{ hours} \]

For the motorboat: \[ \text{time}_\text{motorboat} = \frac{560}{45} = 12.44 \text{ hours} \]

Let's denote the time it takes for them to meet as \( t \) hours.

The total distance covered by both the barge and the motorboat when they meet is 560 km. Therefore, we can write the equation: \[ 25t + 45t = 560 \]

Solving for \( t \): \[ 70t = 560 \] \[ t = \frac{560}{70} \] \[ t = 8 \text{ hours} \]

Answer

They will meet after 8 hours.