Question

Сколько свинца и олова в отдельности содержит кусок сплава в котором олова на 360г. больше чем свинца.Сплав состоит из 2 частей свинца и 5 частей олова.

Answer 1

5-2=3части-на столько частей олова больше чем свинца
360:3=120гр приходится на одну часть
5*120=600гр олова в сплаве
2*120=240гр свинца в сплаве

Answer 2

Calculating the Amount of Lead and Tin in the Alloy

To calculate the amount of lead and tin in the alloy, we can use the following information: - The alloy consists of 2 parts lead and 5 parts tin. - The amount of tin is 360g more than the amount of lead.

Let's denote the amount of lead as x and the amount of tin as y. We can then set up the following equations based on the given information:

1. y = x + 360 (The amount of tin is 360g more than the amount of lead) 2. y = 5x (The alloy consists of 2 parts lead and 5 parts tin)

By substituting the value of y from the second equation into the first equation, we can solve for the amount of lead and tin in the alloy.

Solution

Using the second equation, we can express x in terms of y: x = y / 5

Substitute this value of x into the first equation: y = (y / 5) + 360

Solving for y: y = (1/5)y + 360 y - (1/5)y = 360 (4/5)y = 360 y = 360 * (5/4) y = 450g

Now that we have the amount of tin, we can find the amount of lead: x = 450 / 5 x = 90g

Answer

So, the alloy contains 90g of lead and 450g of tin.