Question

Два самолёта летели с одинаковой скоростью .первый самолёт был в воздухе 4 ч а второй 6 часов первый самолё т пролетел на 1400км менше второго .какое расстояние пролетел второй самолёта

Answer 1

1) 1400:4=350 (км) - пролетает 1 самолет за один час.
2) 350 * 6 =2100 (км) - пролетел 2 самолет.
Ответ: 2100 км.

Answer 2

Problem Analysis

We are given two airplanes that flew at the same speed. The first airplane was in the air for 4 hours, while the second airplane was in the air for 6 hours. The first airplane flew 1400 km less than the second airplane. We need to determine the distance traveled by the second airplane.

Solution

Let's assume that the speed of both airplanes is x km/h.

The distance traveled by the first airplane can be calculated using the formula: distance = speed × time. Therefore, the distance traveled by the first airplane is 4x km.

The distance traveled by the second airplane can also be calculated using the same formula: distance = speed × time. Therefore, the distance traveled by the second airplane is 6x km.

We are given that the first airplane traveled 1400 km less than the second airplane. So we can set up the equation:

4x = 6x - 1400

Now we can solve this equation to find the value of x.

2x = 1400

x = 700

Now that we know the value of x, we can calculate the distance traveled by the second airplane:

distance = speed × time = 700 km/h × 6 hours = 4200 km

Therefore, the second airplane traveled a distance of 4200 km.

Answer

The second airplane traveled a distance of 4200 km.