Question

В одиннадцать ч с аэродрома вылетели одновременно в противоположных направлениях два самолёта. в четырнадцать ч расстояние между ними было 3540 км . один из них летел со скоростью 620 км/ч. с какой скоростью летел другой самолёт?

Answer 1

1) 14-11=3 (часа) - время полёта 

2) 620*3=1860 (км) - рассстояние которое пролетел 1-й самолёт

3) 3540-1860=1680 (км) - рассстояние которое пролетел 2-й самолёт

4)1680:3=560(км/ч) - средняя скорость 2-ого самолёта 

    ОТВЕТ:  560км/ч  - средняя скорость 2-ого самолёта 

Спс и 5!)

Answer 2

Calculation of the Speed of the Second Plane

To calculate the speed of the second plane, we can use the formula:

Speed = Distance / Time

Given that the distance between the two planes at 14:00 was 3540 km and the first plane was flying at a speed of 620 km/h, we can calculate the time it took for the first plane to cover that distance:

Time = Distance / Speed

Time = 3540 km / 620 km/h

Calculating this, we find that the time taken by the first plane to cover the distance was approximately 5.71 hours.

Since the two planes departed simultaneously at 11:00, we can calculate the time difference between their departure and the time at 14:00:

Time difference = 14:00 - 11:00

Converting this to hours, we get:

Time difference = 3 hours

Now, to find the speed of the second plane, we can use the formula:

Speed = Distance / Time

Speed = 3540 km / (5.71 hours + 3 hours)

Calculating this, we find that the speed of the second plane was approximately 354 km/h.

Therefore, the second plane was flying at a speed of 354 km/h.