Question

Один аист летел 5 минут, а другой 8 минут. Один из них пролетел на 1800 км больше второго. Сколько метров пролетел каждый аист, если их скорости были одинаковыми?

Answer 1

8-5=3мин летел больше один аист
1800:3=600км в минуту
600км*5=3000км или 300000м пролетел один аист
600км*8=4800км или 480000м пролетел другой аист
ответ 1-300000м    2-480000м

Answer 2

Problem Analysis

We are given that one stork flew for 5 minutes and the other stork flew for 8 minutes. We are also told that one of the storks flew 1800 km more than the other stork. We need to find out how many meters each stork flew, assuming their speeds were the same.

Solution

Let's assume that the speed of each stork is v meters per minute.

We know that the distance traveled by a stork is equal to the product of its speed and the time it flew. Therefore, the distance traveled by the first stork is 5v meters, and the distance traveled by the second stork is 8v meters.

We are also given that the distance traveled by one stork is 1800 km (or 1800000 meters) more than the distance traveled by the other stork. Therefore, we can set up the following equation:

8v - 5v = 1800000

Simplifying the equation, we get:

3v = 1800000

Dividing both sides of the equation by 3, we find:

v = 600000

Now that we know the value of v, we can calculate the distance traveled by each stork:

- The first stork traveled 5v = 5 * 600000 = 3000000 meters. - The second stork traveled 8v = 8 * 600000 = 4800000 meters.

Therefore, the first stork traveled 3,000,000 meters and the second stork traveled 4,800,000 meters.

Answer

Each stork flew the following distances: - The first stork flew 3,000,000 meters. - The second stork flew 4,800,000 meters.

Please let me know if you need any further assistance!