Question

Велосипедист ехал 2 часа с некоторой скоростью, а затем увеличивая на 1 км/ч ехал еще 3 часа. С какой скоростью ехал он первоначально, есливесь путь равен 63 км?

Answer 1

Х скорость первоначально
2*х+3(х+1)=63
2х+3х+3=63
5х=63-3
х=60/5=12 км/ч начальная скорость

Answer 2

Calculating the Initial Speed of the Cyclist

To calculate the initial speed of the cyclist, we can use the formula: \[ \text{speed} = \frac{\text{distance}}{\text{time}} \]

The total distance traveled by the cyclist is 63 km. Let's denote the initial speed as \( v_1 \) (in km/h) and the increased speed as \( v_2 \) (in km/h).

The cyclist traveled for 2 hours at the initial speed and then for 3 hours at the increased speed. We can set up the following equations based on the given information:

1. \( 2v_1 + 3(v_1 + 1) = 63 \)

Let's solve for the initial speed \( v_1 \) using the given information and the equations.

Solution

Using the given equation, we can solve for the initial speed \( v_1 \):

\[ 2v_1 + 3(v_1 + 1) = 63 \]

Solving for \( v_1 \): \[ 2v_1 + 3v_1 + 3 = 63 \] \[ 5v_1 + 3 = 63 \] \[ 5v_1 = 60 \] \[ v_1 = \frac{60}{5} \] \[ v_1 = 12 \]

So, the initial speed of the cyclist was 12 km/h.