Question

Два самолета летели с одинаковой скоростью один самолёт был в воздухе 4 часа а другой 6 часа пролетел на 1600 км больше чем первый Сколько километров пролетел каждый самолет

Answer 1

6-4=2(ч) 1600 км
1600:2=800(км/ч) скорость самолётов
800*4=3200(км) пролетел первый самолёт
800*6=4800(км) пролетел второй самолёт

Answer 2

Problem Analysis

We are given two airplanes flying at the same speed. One airplane flies for 4 hours, while the other flies for 6 hours and covers a distance that is 1600 km greater than the first airplane. We need to determine the distance covered by each airplane.

Solution

Let's assume that the speed of both airplanes is x km/h.

The distance covered by the first airplane can be calculated by multiplying its speed by the time it flew: 4x km.

The distance covered by the second airplane can be calculated by multiplying its speed by the time it flew: 6x km.

According to the problem, the second airplane covered a distance that is 1600 km greater than the first airplane. Therefore, we can set up the following equation:

6x = 4x + 1600

Simplifying the equation, we get:

2x = 1600

Dividing both sides of the equation by 2, we find:

x = 800

Now that we know the speed of the airplanes is 800 km/h, we can calculate the distance covered by each airplane:

- The first airplane flew for 4 hours, so its distance is 4 * 800 = 3200 km. - The second airplane flew for 6 hours, so its distance is 6 * 800 = 4800 km.

Therefore, the first airplane covered 3200 km, and the second airplane covered 4800 km.

Answer

The first airplane covered a distance of 3200 km, and the second airplane covered a distance of 4800 km.