Question

Олег решил навести своего лучшего друга. Он вышел из дому и пошел со скоростью 48м/мин. Через 5 мин вслед за ним вышел из этого же дома Саша и догнал его через 4 мин у дома друга. С какой скоростью шёл Саша? Помогите с задачей Пожалуйста!!! с меня спасибо и 25 баллов

Answer 1

Олег шел сам 5 мин и еще 4 мин. пока его Саша догонял
5+4=9 мин шел Олег
48 * 9=432м - путь к дому друга
432/4= 108 м/мин - скорость Саши

Answer 2

Problem Analysis

Oleg and Sasha are two friends. Oleg leaves his house and starts walking at a speed of 48 m/min. After 5 minutes, Sasha leaves the same house and catches up with Oleg in 4 minutes. We need to determine Sasha's walking speed.

Solution

Let's assume Sasha's walking speed is x m/min.

We know that Oleg walked for 5 minutes before Sasha started walking. So, the distance covered by Oleg in those 5 minutes is: Distance covered by Oleg = Speed of Oleg * Time taken by Oleg = 48 m/min * 5 min = 240 meters.

Now, Sasha catches up with Oleg in 4 minutes. During this time, Sasha covers the same distance that Oleg covered in 5 minutes. So, the distance covered by Sasha in 4 minutes is also 240 meters.

Using the formula Distance = Speed * Time, we can calculate Sasha's walking speed: 240 meters = x m/min * 4 min.

Simplifying the equation, we have: x = 240 meters / 4 min = 60 m/min.

Therefore, Sasha's walking speed is 60 m/min.

Answer

Sasha walked with a speed of 60 m/min.