Question

К водному раствору кислоты добавили 1 кг воды,отчего его концентрация уменьшилась в 3 раза. Во сколько раз уменьшиться концентрация полученного раствора,если к нему добавить 6 кг воды?

Answer 1

1кг. это 3
6кг. это x
x = 6*3 = 18

Answer 2

В 2 раза...............................

Answer 3

Calculation of Concentration Change

To answer your question, let's calculate the concentration change when 1 kg of water is added to a water solution of acid, resulting in a 3-fold decrease in concentration.

Let's assume the initial concentration of the acid solution is C (in some units, such as moles per liter). When 1 kg of water is added to the solution, the total volume of the solution increases by 1 liter. Therefore, the new volume of the solution is V + 1, where V is the initial volume of the solution.

Since the concentration is defined as the amount of solute divided by the volume of the solution, the new concentration can be calculated as:

C' = C / (V + 1)

Given that the new concentration is 3 times smaller than the initial concentration, we can write the following equation:

C' = C / (V + 1) = C / V / 3

Simplifying the equation, we find:

C' = C / (V + 1) = C / V / 3 3 = V + 1

Solving for V, we get:

V = 2

Therefore, the initial volume of the solution is 2 liters.

Now, let's calculate the concentration change when an additional 6 kg of water is added to the solution.

The new volume of the solution will be V + 6, and the new concentration can be calculated as:

C'' = C' / (V + 6)

Substituting the value of V we found earlier, we get:

C'' = C' / (2 + 6) = C' / 8

Therefore, the concentration of the resulting solution, when 6 kg of water is added, will be 1/8 of the concentration of the initial solution.

Summary

To summarize, when 1 kg of water is added to a water solution of acid, resulting in a 3-fold decrease in concentration, the initial volume of the solution is 2 liters. When an additional 6 kg of water is added, the concentration of the resulting solution will be 1/8 of the concentration of the initial solution.

Please let me know if you have any further questions!