Question

Скорость прямолинейного движения тела задана уравнением V(t)=(3t^2+2)m\c. Найти путь пройденый телом за 3-ю секунду.

Answer 1

Ответ. V(t)=(3*t^2-2*t+3); S(t)=INT(3*t^2-2*t+3)*dt (в пределах 2,3)=t^3-t^2+3*t+C; 
S3=S(3)-S(2)=3^3-3^2+3*3+C-2^3+2^2-3*2-C=27-9+9-8+4-6=17;

Answer 2

Из школьного курса математики...
v=3t^2+2
S=F(t)=t^3+2t
Путь пройденный за 3-ю секунду это разница пути м/у 2й и 3й секундами
S3=27+6-8-4=21м

Answer 3

Calculating Distance Traveled by a Body in Straight-Line Motion

To calculate the distance traveled by a body in straight-line motion at the 3rd second, we can use the equation for velocity provided: V(t) = 3t^2 + 2 m/s.

First, we need to find the displacement function, which is the integral of the velocity function. Then, we can use this displacement function to find the distance traveled at the 3rd second.

The displacement function, denoted as S(t), is the integral of the velocity function V(t) with respect to time t.

The displacement function is given by: **S