Question

Во время соревнований по игре в шашки Костя выйграл 6 раз,а проиграл в двух партиях.Сколько партий он сыграл вничью,если всего он сыграл 12 партий?

Answer 1

12-(6+2)=4 партии
Ответ: Костя сыграл вничью 4 партии.

Answer 2

1) 6 + 2 = 8(партий) . в которых он выиграл и проиграл
2) 12 - 8 = 4(партии)
Ответ: 4 партии Костя сыграл вничью.

Answer 3

Calculating the Number of Draws in Checkers Competition

To calculate the number of draws in Kostya's checkers competition, we can use the information provided.

Kostya won 6 games and lost 2 games, out of a total of 12 games played.

Step 1: Calculate the number of games drawn.

We can use the fact that the total number of games played is 12, and the sum of the games won, lost, and drawn should equal 12.

Step 2: Calculate the number of drawn games.

Let's proceed with the calculation.

Step 1: 12 (total games) = 6 (games won) + 2 (games lost) + x (games drawn)

Step 2: 12 = 6 + 2 + x 12 = 8 + x x = 12 - 8 x = 4

Answer: Kostya played 4 games to a draw.