Question

Для покраски1 кв.м потолка требуется 210 г краски.краска продается в банках по 3кг.какое наименьшее количествобанок краски нужно купить для покраски потолка площадью 46 кв.м

Answer 1

46*210=9660

9660/1000=9,66

9,66/3=3(ост.0,66) --> нужно 4 банки краски

Answer 2

Answer in detail. To paint 1 sq. m of ceiling, 210 g of paint is required. The paint is sold in cans of 3 kg. How many cans of paint do you need to buy to paint a ceiling with an area of 46 sq. m?

To solve this problem, we need to find out how much paint is needed for 46 sq. m of ceiling, and then divide that amount by the capacity of one can of paint. We can use the following steps:

- Step 1: Multiply the area of the ceiling by the amount of paint required for 1 sq. m. This will give us the total amount of paint needed for the ceiling. - Step 2: Divide the total amount of paint by 1000 to convert it from grams to kilograms. This will make it easier to compare with the capacity of one can of paint. - Step 3: Divide the result from step 2 by the capacity of one can of paint. This will give us the number of cans of paint needed for the ceiling. - Step 4: Round up the result from step 3 to the nearest whole number. This is because we cannot buy a fraction of a can of paint, and we need to buy enough paint to cover the whole ceiling.

Using these steps, we can calculate the answer as follows:

- Step 1: 46 x 210 = 9660 g - Step 2: 9660 / 1000 = 9.66 kg - Step 3: 9.66 / 3 = 3.22 - Step 4: 3.22 rounded up to the nearest whole number is 4

Therefore, the answer is 4 cans of paint.