Question

Марат утверждает,что первый арбуз в два раза тяжелее, чем второй, и на 3 кг легче, чем третий. Найдите вес каждого арбуза ,зная, что вместе они весят 33кг.

Answer 1

Ответ:

6

Пошаговое объяснение:

Пусть х это второй арбуз, тогда первый арбуз это 2х, а третий арбуз это 2х+3. Составим уравнение:

х+2х+2х+3=33

5х+3= 33

5х= 33-3

5х= 30

х= 30:5

х=6

Answer 2

Solution:

To solve this problem, we can set up a system of equations based on the given information and then solve for the weights of the three watermelons.

Let's denote the weights of the first, second, and third watermelons as x, y, and z respectively.

We are given the following information: 1. Marat claims that the first watermelon is twice as heavy as the second: x = 2y. 2. The first watermelon is 3 kg lighter than the third: x = z - 3. 3. The total weight of all three watermelons is 33 kg: x + y + z = 33.

We can use these equations to solve for the weights of the three watermelons.

First, we can use the equation x = 2y to express x in terms of y: x = 2y.

Next, we can use the equation x = z - 3 to express z in terms of x: z = x + 3.

Now, we can substitute these expressions into the equation x + y + z = 33: 2y + y + (x + 3) = 33.

Solving for y: 3y + x + 3 = 33, 3y + 2y + 3 + 3 = 33, 5y + 6 = 33, 5y = 27, y = 27 / 5, y = 5.4.

Now that we have the value of y, we can find x and z: x = 2y, x = 2 * 5.4, x = 10.8.

z = x + 3, z = 10.8 + 3, z = 13.8.

Answer:

So, the weights of the three watermelons are: - The first watermelon weighs 10.8 kg - The second watermelon weighs 5.4 kg - The third watermelon weighs 13.8 kg.