Question

Бірлесіп орындалатын жұмыстарға қатысты есептер. 5-сабақ Алмас үйден көлге дейін 40 минутта, ал інісі Асхат 50 минутта жетеді. Егер Асхат ағасына қарағанда үйден 5 минут ерте шықса, онда Алмас қанша уақытта Асхатты қуып жетеді? Жауабы: минутта.

Answer 1

Ответ:

2 минут арасы кажется. Но неуверена

Answer 2

Ответ:15

Пошаговое объяснение:

Дұрыс

Answer 3

This is a question about how to solve a problem involving the time it takes for two people to meet each other when they start from different locations and travel at different speeds. The problem is related to the topic of joint work, which is covered in the 5th grade mathematics curriculum in Kazakhstan. You can find some resources on this topic in the web search results I have provided .

To answer the question, we need to find the distance between Almas's home and the lake, and then use the formula for the rate of change of distance:

distance = speed * time

Let d be the distance between Almas's home and the lake, v1 be Almas's speed, and v2 be Asxat's speed. We know that:

d = v1 * 40 d = v2 * 50

We can solve for v1 and v2 by dividing both sides of the equations by 40 and 50 respectively:

v1 = d / 40 v2 = d / 50

Now, suppose Asxat leaves his home 5 minutes earlier than Almas. This means that he has a head start of 5 minutes, or 1/12 of an hour. Let t be the time it takes for Almas to catch up with Asxat. Then we have:

d = v1 * t d = v2 * (t + 1/12)

We can eliminate d by equating the right-hand sides of the equations:

v1 * t = v2 * (t + 1/12)

We can substitute v1 and v2 with the expressions we found earlier:

(d / 40) * t = (d / 50) * (t + 1/12)

We can simplify this equation by multiplying both sides by 200 and canceling out d:

5 * t = 4 * (t + 1/12)

Expanding the brackets and collecting the terms with t, we get:

t = 1/3

This means that Almas will catch up with Asxat in 1/3 of an hour, or 20 minutes. Therefore, the answer is 20 minutes.