
2. Катер за 3 часа по озеру и за 2 часа против течения реки проплывает такое же расстояние, что
за 4 ч по течению реки. Найдите собственную скорость катера, если скорость течення реки равна 2км/ч.

Ответы на вопрос

Ответ:
пусть х скорость катера,тогда его скорость по течению реки х+2,против течения х-2,3 часа по озеру 3х
составляем уравнение:
3х+2(х-2)=4(х+2)
3х+2х-4=4х+8
5х-4х=8+4
х=12км/ч
Ответ:12 км/ч собственная скорость катера
Пошаговое объяснение:
Надеюсь помогла :3



Problem Analysis
We are given that a boat travels the same distance in 3 hours on a lake and in 2 hours against the current of a river. We are also given that the boat travels the same distance in 4 hours with the current of the river. We need to find the speed of the boat.Solution
Let's assume the speed of the boat in still water is x km/h and the speed of the river's current is 2 km/h.When the boat is traveling on the lake, it is not affected by any current, so its effective speed is equal to its speed in still water. Therefore, the distance traveled on the lake is 3x km.
When the boat is traveling against the current of the river, the effective speed of the boat is reduced by the speed of the current. Therefore, the distance traveled against the current is 2(x - 2) km.
When the boat is traveling with the current of the river, the effective speed of the boat is increased by the speed of the current. Therefore, the distance traveled with the current is 4(x + 2) km.
According to the problem, the distance traveled on the lake is equal to the distance traveled with the current. Therefore, we can set up the following equation:
3x = 4(x + 2)
Let's solve this equation to find the value of x:
3x = 4x + 8
3x - 4x = 8
-x = 8
x = -8
Since the speed of the boat cannot be negative, we can conclude that there is no solution to this problem.
Therefore, there is no valid speed for the boat that satisfies the given conditions.
Conclusion
Based on the given information, there is no valid speed for the boat that satisfies the conditions of traveling the same distance in different scenarios.

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