Question

Бросаются 2 игральные кости . Какова вероятность появления хотя бы одной шестерки?

Answer 1

Ответ: 11/36

Пошаговое объяснение:

Пусть событие A – хотя бы на одной грани выпало 6 очков.

n = 6 × 6 = 36, m = 11. Тогда искомая вероятность

р = 11/36

Answer 2

Вероятность события вычисляется по формуле $\boxed{\rm P=\dfrac{m}{n}}$

Число всевозможных исходов = $6^2$

Число благоприятных исходов: перечислим все пары выпадения очков, в которых будут хотя бы одна шестёрка.

{1;6}; {2;6}, {3;6}, {4;6}, {5;6}, {6;1}, {6;2}, {6;3}, {6;4}, {6;5}, {6;6} - 11 шт

$\rm P=\dfrac{m}{n}=\dfrac{11}{36}$

Ответ: $\rm P=\dfrac{11}{36}$

Answer 3

Probability of Getting at Least One Six on Two Dice

When two dice are thrown, the total number of possible outcomes is 36 (6 faces on the first die multiplied by 6 faces on the second die). The number of outcomes where at least one six appears can be calculated as follows:

1. Calculate the Total Number of Outcomes (n): - The total number of outcomes when two dice are thrown is 36.

2. Calculate the Number of Favorable Outcomes (m): - The number of outcomes where at least one six appears can be calculated by subtracting the outcomes where no six appears from the total outcomes. - The outcomes where no six appears are (1,1), (1,2), (1,3), (1,4), (1,5), (2,1), (2,2), (2,3), (2,4), (2,5), (3,1), (3,2), (3,3), (3,4), (3,5), (4,1), (4,2), (4,3), (4,4), (4,5), (5,1), (5,2), (5,3), (5,4), (5,5). - The outcomes where at least one six appears are (1,6), (2,6), (3,6), (4,6), (5,6), (6,1), (6,2), (6,3), (6,4), (6,5), (6,6). - Therefore, the number of favorable outcomes is 11.

3. Calculate the Probability (P): - The probability of getting at least one six is the ratio of the number of favorable outcomes to the total number of outcomes. - The probability (P) can be calculated as: \[ P = \frac{m}{n} = \frac{11}{36} \]

The probability of getting at least one six when two dice are thrown is approximately 0.3056.

[[SOURCE #1]]