Question

В прямоугольном треугольнике ABC угол С=90 градусам.Внешний угол при вершине В равен 115 градусам.Найдите острые углы прямоугольника Помогите пожалуйста

Answer 1

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Answer 2

Given Information:

We are given that in right triangle ABC, angle C is 90 degrees and the external angle at vertex B is 115 degrees. We need to find the acute angles of the right triangle.

Solution:

In a right triangle, the sum of the acute angles is always 90 degrees. Since angle C is already 90 degrees, we can find the other acute angle by subtracting the external angle at vertex B from 180 degrees.

Let's calculate the acute angles:

1. Angle C = 90 degrees (given) 2. External angle at vertex B = 115 degrees (given) 3. Acute angle at vertex B = 180 degrees - 115 degrees = 65 degrees

Therefore, the acute angles of the right triangle ABC are: - Angle C = 90 degrees - Acute angle at vertex B = 65 degrees

I hope this helps! Let me know if you have any further questions.