Question

7 Реши задачу. В бассейне открыты две трубы. Через одну вода вливается со скоростью 50 м3/ч, через другую — выливается со скоростью 40 м3/ч. Бассейн был пуст, когда открыли обе трубы. Через какое время в бассейне будет 270 м3 воды? 50 м3/ч 40 м3/ч​

Answer 1

Ответ:

Через одну вода вливается со скоростью 50м/ч, через другую-

выливается со скоростью 40м/ч.

Пошаговое объяснение:

50-40=10м/ч вливается

270/10=27ч

Ответ: за 27 часов

Answer 2

Problem Analysis

We have two pipes in a pool. One pipe fills the pool at a rate of 50 m^3/h, while the other pipe drains the pool at a rate of 40 m^3/h. We need to determine how long it will take for the pool to contain 270 m^3 of water.

Solution

To solve this problem, we need to find the net rate at which water is being added to the pool. This can be calculated by subtracting the rate at which water is being drained from the rate at which water is being filled.

Let's denote the rate at which water is being filled as F = 50 m^3/h and the rate at which water is being drained as D = 40 m^3/h.

The net rate of filling the pool can be calculated as F - D = 50 m^3/h - 40 m^3/h = 10 m^3/h.

Now, we can calculate the time it will take to fill the pool with 270 m^3 of water using the formula:

Time = Volume / Rate

Substituting the values, we have:

Time = 270 m^3 / 10 m^3/h = 27 hours.

Therefore, it will take 27 hours for the pool to contain 270 m^3 of water.

Answer

The pool will contain 270 m^3 of water after approximately 27 hours.