Question

Mass volume density A block of tin has a mass of 2193 kg and a volume of 0.3 m³. - Calculate the density of the block of tin, in kg/m³. If your answer is a decimal, give it to 1 d.p. Будь ласка допоможіть даю 50 балів /Please help me

Answer 1

Ответ:

Density (ρ) is defined as the mass (m) of a substance per unit volume (V), so we can use the given mass and volume of the tin block to calculate its density:

ρ = m/V

Substituting the given values, we get:

ρ = 2193 kg / 0.3 m³

ρ ≈ 7310 kg/m³ (to 1 decimal place)

Therefore, the density of the tin block is approximately 7310 kg/m³.

Пошаговое объяснение:

Answer 2

Sure, I'll be happy to help you with that!

Density is calculated using the formula:

\[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \]

In this case, the mass of the block of tin is given as \(2193 \, \text{kg}\), and the volume is given as \(0.3 \, \text{m}^3\).

Substitute these values into the formula:

\[ \text{Density} = \frac{2193 \, \text{kg}}{0.3 \, \text{m}^3} \]

Now, perform the division:

\[ \text{Density} = 7301 \, \text{kg/m}^3 \]

So, the density of the block of tin is \(7301 \, \text{kg/m}^3\). If you need to round the answer to one decimal place, it would be \(7301.0 \, \text{kg/m}^3\).

I hope this helps! If you have any further questions, feel free to ask.