Question

Cos 6 alpha +2 sin ^2 3 alpha​

Answer 1

Ответ:

решение смотри на фотографии

Пошаговое объяснение:

Answer 2

Ответ:

ето правильно пишется 7

Answer 3

The expression you've provided, `cos(6α) + 2sin^2(3α)`, is a trigonometric identity that can be simplified using various trigonometric identities.

One of the most useful identities in this case is the double-angle formula for sine and cosine, which states that `sin(2x) = 2sin(x)cos(x)` and `cos(2x) = cos^2(x) - sin^2(x)`. Additionally, the Pythagorean identity `sin^2(x) + cos^2(x) = 1` is also useful in this case .

Let's start by simplifying `cos(6α)`. Using the double-angle formula, we can rewrite this as `cos^2(3α) - sin^2(3α)`.

Next, let's simplify `2sin^2(3α)`. Using the double-angle formula again, this can be rewritten as `2sin^2(3α) = 2(2sin(3α)cos(3α)) = 4sin(3α)cos(3α)`.

Now, we can combine these two expressions to get `cos^2(3α) - sin^2(3α) + 4sin(3α)cos(3α)`.

Finally, we can use the Pythagorean identity to rewrite this as `cos^2(3α) + 4sin(3α)cos(3α) - sin^2(3α)`. This simplifies to `cos^2(3α) + 3sin(3α)cos(3α)`.

So, the expression `cos(6α) + 2sin^2(3α)` simplifies to `cos^2(3α) + 3sin(3α)cos(3α)`.

This is a simplified form of the original expression, but without additional context or information, it's not possible to simplify it further.