Question

две снегоуборочные машины одновременно выехали в 8:00 утра и поехали в одном направлении в 11:00 утра расстояние между ними было 6 км с какой скоростью двигалось первая машина если скорость второй машины 30 км ч.Решить задачу уравнением​

Answer 1

Первая машина двигалась со скоростью x км/ч.

11-8 = 3 часа были машины в пути.

Далее два варианта:

1 - скорость первой машины больше, чем скорость второй

x-30 км/ч скорость отдаления

(x-30)·3 = 6

x-30 = 6:3

x-30 = 2

x = 2+30

x = 32 км/ч скорость первой машины.

2 - скорость первой машины меньше, чем скорость второй

30-x км/ч скорость отдаления

(30-x)·3 = 6

30-x = 6:3

30-x = 2

x = 30-2

x = 28 км/ч скорость первой машины.

Answer 2

#### Problem Analysis We are given that two snowplows started simultaneously at 8:00 AM and traveled in the same direction. At 11:00 AM, the distance between them was 6 km. We are also given that the second snowplow was traveling at a speed of 30 km/h. We need to find the speed of the first snowplow. #### Solution Let's assume that the speed of the first snowplow is **v** km/h. From 8:00 AM to 11:00 AM, a total of 3 hours have passed. During this time, the second snowplow, traveling at a speed of 30 km/h, has covered a distance of 30 km/h * 3 h = 90 km. The distance between the two snowplows at 11:00 AM was 6 km. This means that the first snowplow has covered a distance of 90 km + 6 km = 96 km. We can use the formula **distance = speed * time** to find the speed of the first snowplow. **96 km = v km/h * 3 h** Simplifying the equation, we get: **v km/h = 96 km / 3 h** Calculating the result: **v km/h = 32 km/h** Therefore, the speed of the first snowplow is **32 km/h**. #### Answer The first snowplow was moving at a speed of **32 km/h**.