Question

Знаменитый преступник профессор Мориарти проник в банк, но так и не смог подобрать трехзначный код от сейфа. Шерлок Холмс поотпечаткам пальцев обнаружил, что Мориарти успел попробоватькомбинации 543, 142 и 562, после чего его спугнул охранник.Оказалось, что в каждом из этих вариантов профессор угадал ровноодну цифру кода. Узнав это, Шерлок Холмс тут же сказал код отсейфа. А вы сможете?​

Answer 1

Ответ:

316

Пошаговое объяснение:

в 543 142 562

Жирным отмечены цифры которые повторяются

Answer 2

#### The Code to the Safe The famous criminal mastermind Professor Moriarty attempted to break into a bank but was unable to crack the three-digit code to the safe. Sherlock Holmes, using fingerprint analysis, discovered that Moriarty had tried the combinations 543, 142, and 562, and in each of these attempts, he correctly guessed one digit of the code. Upon learning this information, Sherlock Holmes immediately deduced the code to the safe. Can you figure it out? To solve this puzzle, we need to analyze the information provided. Moriarty tried three different combinations: 543, 142, and 562. In each attempt, he correctly guessed one digit of the code. This means that there is one digit that appears in all three combinations. By examining the combinations, we can identify the common digit: - Combination 543: Moriarty guessed one digit correctly. - Combination 142: Moriarty guessed one digit correctly. - Combination 562: Moriarty guessed one digit correctly. From these combinations, we can see that the digit 2 appears in all three attempts. Therefore, the code to the safe must include the digit 2. Now, we need to determine the other two digits of the code. Since Moriarty correctly guessed one digit in each attempt, we can conclude that the remaining two digits are not present in any of the combinations. To find the other two digits, we can look at the digits that are not present in any of the combinations: 0, 1, 3, 4, 5, 6, 7, 8, and 9. We know that the code is a three-digit number, so we have nine options for the first digit, nine options for the second digit, and eight options for the third digit (since we have already determined that the code includes the digit 2). Therefore, the total number of possible codes is 9 * 9 * 8 = 648. To narrow down the possibilities further, we can use the fact that Moriarty correctly guessed one digit in each attempt. This means that the other two digits of the code cannot be the same as the digits he guessed correctly. Let's go through the remaining digits and eliminate the ones that Moriarty guessed correctly: - Combination 543: Moriarty guessed the digit 4 correctly, so we can eliminate 4 as a possibility for the other two digits. - Combination 142: Moriarty guessed the digit 1 correctly, so we can eliminate 1 as a possibility for the other two digits. - Combination 562: Moriarty guessed the digit 2 correctly, but we already know that the code includes the digit 2. After eliminating these digits, we are left with the following possibilities for the other two digits: 0, 3, 5, 6, 7, 8, and 9. Now, we need to find a combination of these digits that includes the digit 2. By trying out different combinations, we can find that the code to the safe is **205**. Therefore, the code to the safe is 205. Sherlock Holmes was able to deduce this by analyzing the combinations Moriarty attempted and identifying the common digit in all three attempts. I hope this helps! Let me know if you have any further questions.