
Вдоль дороги расположены 5 домов.Расстояние между каждым 2 соседними домами равно 10 м. Возле
какого дома надо вырыть колодец , чтобы сумма расстояний от колодца до домов была как можно меньшей . Чему равно это расстояние ?

Ответы на вопрос

расстояние от 1 дома до 5 дома 50м
расстояние от 1 дома до колодца 25м
10×5=50 а дальше разумно что возле
третьего дома



Problem Analysis
We have 5 houses located along a road, with a distance of 10 meters between each neighboring house. We need to determine which house to dig a well near in order to minimize the sum of the distances from the well to each house.Solution
To solve this problem, we can consider the distances from the well to each house and calculate the sum of these distances for each house. The house with the minimum sum of distances will be the optimal choice for digging the well.Let's calculate the sum of distances from the well to each house:
- Distance from the well to the first house: 0 meters (since the well is located near the first house). - Distance from the well to the second house: 10 meters. - Distance from the well to the third house: 20 meters. - Distance from the well to the fourth house: 30 meters. - Distance from the well to the fifth house: 40 meters.
Therefore, the sum of distances from the well to each house is as follows:
- Sum of distances for the first house: 0 meters. - Sum of distances for the second house: 10 meters. - Sum of distances for the third house: 20 meters. - Sum of distances for the fourth house: 30 meters. - Sum of distances for the fifth house: 40 meters.
From the calculations above, we can see that the sum of distances is the smallest for the first house, which means that digging the well near the first house will result in the minimum sum of distances.
Therefore, the optimal choice for digging the well is near the first house, and the distance from the well to the first house is 0 meters.
Conclusion
In order to minimize the sum of distances from the well to each house, it is recommended to dig the well near the first house, resulting in a distance of 0 meters between the well and the first house.

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