Question

A+3 <4*(3a+7)+14*(5-a)​

Answer 1

Ответ:

Пошаговое объяснение:

a3 = a1+2d=7,5

a7 = a1+6d=14,3

Вычтем из второго первое

4d = 14,3 - 7,5 = 6,8

d= 6,8/4 = 1,7

a1 = 7,5-2*d = 7,5-3,4 = 4,1

Answer 2

To solve the inequality A + 3 < 4(3A + 7) + 14(5 - A), you can follow these steps:

1. First, distribute the constants on the right side of the inequality: A + 3 < 12A + 28 + 70 - 14A

2. Next, simplify the expression by combining like terms: A + 3 < -2A + 98

3. To isolate the variable A on one side, you can add 2A to both sides of the inequality to get all the A terms on the left side: A + 2A + 3 < 2A - 2A + 98

   This simplifies to: 3A + 3 < 98

4. Now, subtract 3 from both sides to isolate 3A: 3A + 3 - 3 < 98 - 3

   This simplifies to: 3A < 95

5. Finally, divide both sides by 3 to solve for A: (3A)/3 < 95/3

   A < 95/3

So the solution to the inequality A + 3 < 4(3A + 7) + 14(5 - A) is:

A < 95/3