Question

Алгебра 9-класс 13вариант Смотреть ответ alex080297 alex080297 3x+7≥5x+10 3x+7=5x+10 -2x=3 x=-1.5 x∈[-1.5;-∞)

Answer 1

Algebra 9th Grade - 13th Variant

The given equation is: 3x + 7 ≥ 5x + 10.

To solve this equation, we need to isolate the variable x on one side of the inequality.

Solving the Inequality

1. Subtract 3x from both sides of the equation: 3x + 7 - 3x ≥ 5x + 10 - 3x. Simplifying, we get: 7 ≥ 2x + 10.

2. Subtract 10 from both sides of the equation: 7 - 10 ≥ 2x + 10 - 10. Simplifying, we get: -3 ≥ 2x.

3. Divide both sides of the equation by 2 (since the coefficient of x is 2): -3/2 ≥ 2x/2. Simplifying, we get: -3/2 ≥ x.

Therefore, the solution to the inequality is x ≤ -3/2.

Interval Notation

In interval notation, the solution can be represented as x ∈ (-∞, -3/2].

I hope this helps! Let me know if you have any further questions.