
Y=√x+2y=√x-3y=(x-4)^2y=(x+2)^2-3


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Ответ:
скажи что нужно сделать с этим



It seems like you've provided a system of equations with multiple variables: x and y. To solve this system, we can use the method of substitution. We'll start by solving one equation for one variable and then substitute that expression into the other equations. Let's proceed step by step:
Start with the first equation: y = √x
Now, substitute this expression for y into the second equation: √x + 2√x = √x - 3y
Simplify the equation: 3√x = -3y
Divide both sides by 3 to isolate y: y = -√x
Now, substitute the expression for y into the third equation: (x - 4)^2(-√x) = (x + 2)^2 - 3
Expand and simplify the equation: (x^2 - 8x + 16)(-√x) = x^2 + 4x + 4 - 3
Distribute the -√x on the left side: -x^(5/2) + 8x^(3/2) - 16x^(1/2) = x^2 + 4x + 1
Rearrange terms and collect like terms on the left side: -x^(5/2) + 8x^(3/2) - 16x^(1/2) - x^2 - 4x - 1 = 0
Now you have a single equation in terms of x. This is a polynomial equation of degree 5/2, which isn't straightforward to solve analytically. You may need to use numerical methods or a graphing calculator to find approximate solutions for x. Once you have those values for x, you can use the expressions for y you derived earlier to find the corresponding y-values.


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