Question

A^4-81 уравнение 3х^2-12x=0 49x^2+14x^2+x=0 x^3-5x^2-x+5=0

Answer 1

1)a^4=81
a=3
2)x(3x-12)=0
x=0 ili 3x=12
x=4
63x^2+x=0
x(63x+1)=0
x=0. 63x+1=0
63x=-1
x=-1/63
x(x^2-5x-1+5)=0
x=0 x^2-5x+4=0
d=25-16=9
x=5+3/2=4
x=5-3/2=1
ответ :0,1,4

Answer 2

It seems like you have provided several equations, and I will help you solve each of them.

1. A^4 - 81 = 0

   This is a simple quadratic equation, where A^4 is a term. To solve it, you can factor it as the difference of squares:

   A^4 - 81 = (A^2 + 9)(A^2 - 9) = (A^2 + 9)(A + 3)(A - 3) = 0

   Now, set each factor equal to zero:

   A^2 + 9 = 0, A + 3 = 0, A - 3 = 0

   Solving for A in each equation:

   A^2 = -9 has no real solutions. A + 3 = 0, so A = -3. A - 3 = 0, so A = 3.

   So, the solutions are A = -3 and A = 3.

2. 3x^2 - 12x = 0

   This is a quadratic equation. Factor out the common term:

   3x(x - 4) = 0

   Now, set each factor equal to zero:

   3x = 0, x - 4 = 0

   Solving for x in each equation:

   3x = 0, so x = 0. x - 4 = 0, so x = 4.

   The solutions are x = 0 and x = 4.

3. 49x^2 + 14x^2 + x = 0

   Combine the like terms:

   63x^2 + x = 0

   This is also a quadratic equation. To solve it, factor out the common term:

   x(63x + 1) = 0

   Now, set each factor equal to zero:

   x = 0, 63x + 1 = 0

   Solving for x in each equation:

   x = 0. 63x + 1 = 0, so 63x = -1, and x = -1/63.

   The solutions are x = 0 and x = -1/63.

4. x^3 - 5x^2 - x + 5 = 0

   This is a cubic equation. To solve it, you can try factoring, but it's not a straightforward process, so you might want to use numerical methods or a graphing calculator to approximate the solutions. The solutions are not immediately apparent from factoring.

Please let me know if you need further assistance with any of these equations.