Question

13 11/12-10 4 4/15-2 1/30 12 1/5+2 5/10 15 1/7-5 16 2/9+2 1/18

Answer 1

13 11/12-10=3 11/12

4 4/15-2 1/30= 4 8/30- 2 1/30=2 7/30

12 1/5+2 5/10= 12 2/10 - 2 5/10 =9 7/10

15 1/7-5 = 10 1/7

16 2/9+2 1/18= 16 4/18 + 2 1/18= 18 5/18

Answer 2

13 11/12-10 =13 11/12

4 4/15-2 1/30 = 4 целых 4*2/30 - 2 целых 1*1/

Answer 3

To perform these arithmetic operations, we'll start by simplifying each fraction, then perform the addition or subtraction. Let's break it down step by step:

1. $13 \frac{11}{12} - 10$ To subtract mixed numbers, we first need to convert them to improper fractions. $13 \frac{11}{12} = \frac{12 \cdot 13 + 11}{12} = \frac{156 + 11}{12} = \frac{167}{12}$ Now, subtract: $\frac{167}{12} - 10 = \frac{167}{12} - \frac{120}{12} = \frac{167 - 120}{12} = \frac{47}{12}$

2. $4 \frac{4}{15} - 2 \frac{1}{30}$ Convert to improper fractions: $4 \frac{4}{15} = \frac{15 \cdot 4 + 4}{15} = \frac{64}{15}$ $2 \frac{1}{30} = \frac{30 \cdot 2 + 1}{30} = \frac{61}{30}$ Now, subtract: $\frac{64}{15} - \frac{61}{30}$ To subtract fractions with different denominators, find a common denominator, which is 30 in this case: $\frac{64}{15} - \frac{61}{30} = \frac{128}{30} - \frac{61}{30} = \frac{128 - 61}{30} = \frac{67}{30}$

3. $12 \frac{1}{5} + 2 \frac{5}{10}$ Convert to improper fractions: $12 \frac{1}{5} = \frac{5 \cdot 12 + 1}{5} = \frac{61}{5}$ $2 \frac{5}{10} = \frac{10 \cdot 2 + 5}{10} = \frac{25}{10} = \frac{5}{2}$ Now, add: $\frac{61}{5} + \frac{5}{2}$ To add fractions, find a common denominator, which is 10 in this case: $\frac{61}{5} + \frac{5}{2} = \frac{122}{10} + \frac{25}{10} = \frac{122 + 25}{10} = \frac{147}{10} = 14 \frac{7}{10}$

4. $15 \frac{1}{7} - 5 \frac{16}{9}$ Convert to improper fractions: $15 \frac{1}{7} = \frac{7 \cdot 15 + 1}{7} = \frac{106}{7}$