Question

F'(x), kalle f(x) = (2x-3) (3x + 1)

Answer 1

Ответ:f(x)=(2x-3)(3x+1)

0=(2x-3)(3x+1)=0

2x-3=0

3x+1=0

x=дробом 3/2

x= добром -1/3

x1= дробом -1/3

х2 = дробом 3/2

Пошаговое объяснение:

Answer 2

To find the derivative F'(x) of the function f(x) = (2x - 3)(3x + 1), you can use the product rule. The product rule states that if you have two functions u(x) and v(x), then the derivative of their product u(x)v(x) is given by:

(uv)' = u'v + uv'

In your case, u(x) = 2x - 3 and v(x) = 3x + 1. Let's find the derivatives of these two functions first:

u'(x) = d/dx (2x - 3) = 2 v'(x) = d/dx (3x + 1) = 3

Now, apply the product rule:

F'(x) = (2x - 3)(3) + (2)(3x + 1)

Now, simplify:

F'(x) = 6x - 9 + 6x + 2

Combine like terms:

F'(x) = 12x - 7

So, the derivative of the function f(x) = (2x - 3)(3x + 1) is F'(x) = 12x - 7.