Question

1) x2 + bx - ax - ab; 2) x2 - cx + bx - bc;​

Answer 1

Ответ:

1). (x^2+bx)-(ax+ab)=x*(x+b)-a*(x+b)=(x+b)*(x-a);

2). (x^2-cx)+(bx-bc)=x*(x-c)+b*(x-c)=(x-c)*(x+b)

Answer 2

It seems like you have two expressions, and you'd like to simplify or factor them. Let's work through each one:

1. x^2 + bx - ax - ab:

First, let's group the terms with x together and the constants together:

x^2 + bx - ax - ab = (x^2 + bx) - (ax + ab)

Now, we can factor out common terms from each group:

x(x + b) - a(x + b)

Notice that we have a common factor of (x + b) in both terms. Let's factor it out:

(x + b)(x - a)

So, the simplified expression is (x + b)(x - a).

2. x^2 - cx + bx - bc:

Again, let's group the terms with x together and the constants together:

x^2 - cx + bx - bc = (x^2 - cx) + (bx - bc)

Now, we can factor out common terms from each group:

x(x - c) + b(x - c)

Notice that we have a common factor of (x - c) in both terms. Let's factor it out:

(x - c)(x + b)

So, the simplified expression is (x - c)(x + b).