Question

Помогите пожалуйста 1) 5+7x-12/3=x+13 2)74-1/12-y+1/4=2y+5/3​

Answer 1

Ответ:

Надеюсь правильно

Обьяснение:

Answer 2

Sure, I can help you solve these equations. Let's start with the first one:

$5 + \frac{7x - 12}{3} = x + 13$

To solve for $x$, we can start by getting rid of the fraction. Multiply every term by 3 to clear the fraction:

$3(5) + 7x - 12 = 3(x + 13)$

Now, simplify each side:

$15 + 7x - 12 = 3x + 39$

Combine like terms:

$7x + 3 = 3x + 39$

Subtract $3x$ from both sides:

$4x + 3 = 39$

Subtract 3 from both sides:

$4x = 36$

Divide by 4:

$x = 9$

Now, let's move on to the second equation:

$74 - \frac{1}{12} - y + \frac{1}{4} = 2y + \frac{5}{3}$

First, let's combine the constants on the left side:

$74 - \frac{1}{12} + \frac{1}{4} - y = 2y + \frac{5}{3}$

To clear the fractions, let's find a common denominator, which is 12 in this case:

$12(74) - 12 \cdot \frac{1}{12} + 3 \cdot \frac{1}{4} - 12y = 12(2y) + 4 \cdot \frac{5}{3}$

Simplify each side:

$888 - 1 + 3 - 12y = 24y + \frac{20}{3}$

Combine like terms:

$890 - 12y = 24y + \frac{20}{3}$

Add $12y$ to both sides:

$890 = 36y + \frac{20}{3}$

Subtract $\frac{20}{3}$ from both sides:

$2670 = 108y + 20$

Subtract 20 from both sides:

$2650 = 108y$

Divide by 108:

$y = \frac{2650}{108}$

If you want, you can simplify this fraction, but it's a bit messy.