Question

A1 + а2=22; а1*а2=200​

Answer 1

Ответ:

1 пример

а =22/3

2пример

а=200/3

Answer 2

To solve for the values of $a_1$ and $a_2$ in the equations:

1. $a_1 + a_2 = 22$
2. $a_1 \cdot a_2 = 200$

You can use a system of equations.

First, let's solve equation (1) for one of the variables, say $a_1$:

$a_1 = 22 - a_2$

Now, substitute this expression for $a_1$ into equation (2):

$(22 - a_2) \cdot a_2 = 200$

Expand the equation:

$22a_2 - a_2^2 = 200$

Rearrange the equation:

$a_2^2 - 22a_2 + 200 = 0$

Now, you have a quadratic equation in $a_2$. You can solve it using the quadratic formula:

$a_2 = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

In this case, $a = 1$, $b = -22$, and $c = 200$. Plug these values into the formula:

$a_2 = \frac{-(-22) \pm \sqrt{(-22)^2 - 4(1)(200)}}{2(1)}$

Simplify:

$a_2 = \frac{22 \pm \sqrt{484 - 800}}{2}$

$a_2 = \frac{22 \pm \sqrt{-316}}{2}$

Since the discriminant $\Delta$ ($484 - 800$) is negative, there are no real solutions for $a_2$. This means there are no real values of $a_1$ and $a_2$ that satisfy both equations simultaneously.

If you allow complex solutions, you can proceed further to find complex values for $a_1$ and $a_2$.