Question

60 - 6b 4x- 12y- 4 -5а + 15y 12x + 24 b -4 d+ 8b+4

Answer 1

Ответ:

60 — 6в=6(10—в)

4х —12у—4= 4(х—3у—1)

—5а + 15у=—5(а—3у)

12х+24в=12(х+2в)

Answer 2

It seems like you've provided an expression with variables and arithmetic operations. Let's simplify it step by step:

The expression is:

60 - 6b + 4x - 12y - 4 - 5a + 15y + 12x + 24b - 4d + 8b + 4

Now, let's group like terms:

(60 - 4) + (-5a) + (-6b + 12x + 8b) + (-12y + 15y) - 4d

Combine the constants:

56 - 5a + (2x + 2b) + 3y - 4d

So, the simplified expression is:

56 - 5a + 2x + 2b + 3y - 4d