Question

(5+х)*(2-х)*(х-10)=0

Answer 1

Ответ:

х₁ = -5

х₂=2

х₃ = 10

Пошаговое объяснение:

(5+х)*(2-х)*(х-10)=0

5+х = 0; 2-х = 0;  х-10 = 0

х₁ = -5

х₂=2

х₃ = 10

Answer 2

To solve the given equation $(5+x) \cdot (2-x) \cdot (x-10) = 0$, we need to find the values of $x$ that satisfy this equation.

The given equation is a product of three expressions, and for the whole product to be equal to zero, at least one of the three factors must be equal to zero. Therefore, we can set each factor equal to zero and solve for $x$ in each case:

1. $5 + x = 0$ $x = -5$

2. $2 - x = 0$ $x = 2$

3. $x - 10 = 0$ $x = 10$

So, the values of $x$ that satisfy the equation are $x = -5$, $x = 2$, and $x = 10$.