Question

№499. 1)-3/4×7×(-1. 1/3); 2)5/6×(-8)×3/5; 3)-5/9×(-11)×1`4/5; 4)1. 1/2×(-5)×(-2/3); 5)3/8×(-13)×2. 2/3; 6)-1. 3/7×(-9)×(-7/10);​

Answer 1

Ответ на фото, удачи тебе :)

Answer 2

To simplify these expressions, you can follow the order of operations, which is parentheses, exponents, multiplication and division (from left to right), and addition and subtraction (from left to right). Let's solve each of these expressions step by step:

1. $-\frac{3}{4} \times 7 \times \left(-1 \frac{1}{3}\right)$

First, deal with the mixed number $-1 \frac{1}{3}$ by converting it to an improper fraction: $-1 \frac{1}{3} = -\frac{4}{3}$

Now, the expression becomes: $-\frac{3}{4} \times 7 \times (-\frac{4}{3})$

Cancel out common factors: $-\frac{3}{\cancel{4}} \times \cancel{7} \times (-\frac{4}{\cancel{3}}) = -\frac{3}{1} \times (-\frac{4}{1}) = -3 \times (-4) = 12$

2. $\frac{5}{6} \times (-8) \times \frac{3}{5}$

Cancel out common factors: $\frac{\cancel{5}}{6} \times (-\frac{8}{1}) \times \frac{3}{\cancel{5}} = \frac{1}{\cancel{6}} \times (-8) \times \frac{\cancel{3}}{1} = -\frac{8}{6} = -\frac{4}{3}$

3. $-\frac{5}{9} \times (-11) \times \frac{14}{5}$

Cancel out common factors: $-\frac{5}{\cancel{9}} \times (-\frac{11}{1}) \times \frac{\cancel{14}}{5} = -\frac{5}{1} \times (-\frac{11}{1}) \times \frac{2}{1} = -5 \times (-11) \times 2 = 110$

4. $1 \frac{1}{2} \times (-5) \times (-\frac{2}{3})$

Convert the mixed number to an improper fraction: $1 \frac{1}{2} = \frac{3}{2}$

Now, the expression becomes: $\frac{3}{2} \times (-5) \times (-\frac{2}{3})$

Cancel out common factors: $\frac{\cancel{3}}{2} \times (-5) \times (-\frac{\cancel{2}}{3}) = \frac{1}{1} \times (-5) \times \frac{1}{1} = -5$