Question

(a+b)×c=ac+b a=0,4;b=-7;c=-1,3

Answer 1

Пошаговое объяснение:

если не поймёшь напиши я потом напишу

Answer 2

To evaluate the expression (a+b)×c = ac + b for the given values of a, b, and c, you can substitute the values into the expression and calculate the result.

Let's calculate the expression for each combination of a, b, and c:

1. When a = 0, b = -7, and c = -1: (a + b) × c = (0 + (-7)) × (-1) = (-7) × (-1) = 7 ac + b = (0 × (-1)) + (-7) = 0 - 7 = -7

   So, (a + b) × c equals 7, and ac + b equals -7. They are not equal in this case.

2. When a = 0, b = -7, and c = 3: (a + b) × c = (0 + (-7)) × 3 = (-7) × 3 = -21 ac + b = (0 × 3) + (-7) = 0 - 7 = -7

   So, (a + b) × c equals -21, and ac + b equals -7. They are not equal in this case.

3. When a = 4, b = -7, and c = -1: (a + b) × c = (4 + (-7)) × (-1) = (-3) × (-1) = 3 ac + b = (4 × (-1)) + (-7) = -4 - 7 = -11

   So, (a + b) × c equals 3, and ac + b equals -11. They are not equal in this case.

4. When a = 4, b = -7, and c = 3: (a + b) × c = (4 + (-7)) × 3 = (-3) × 3 = -9 ac + b = (4 × 3) + (-7) = 12 - 7 = 5

   So, (a + b) × c equals -9, and ac + b equals 5. They are not equal in this case.

In none of the four combinations of a, b, and c do (a + b) × c and ac + b equal the same value. Therefore, the statement "(a+b)×c=ac+b" is not true for the given values of a, b, and c.