Question

1)|2х-8|×(х-18)=02)|х-4|×(2х+7)=₽3)|24+2х|×(10х-6)=04)|5х+600|×(х-6)=0​

Answer 1

Ответ:

1)

$|2x - 8| = 0 \\ x - 18 = 0 \\ \\ x = 4 \\ x - 18 = 0 \\ \\ x {}^{1} = 4 \\ x {}^{2} = 18$

2)

$|x - 4| = 0 \\ 2x + 7 = 0 \\ \\ x = 4 \\ x = - \frac{7}{2} \\ \\ x {}^{1} = - \frac{7}{2} \\ x {}^{2} = 4$

3)

$|24 + 2x| = 0 \\ 10x - 6 = 0 \\ \\ x = - 12 \\ 10x - 6 = 0 \\ \\ x = - 12 \\ x = \frac{3}{5} \\ \\ x {}^{1} = - 12 \\ x {}^{2} = \frac{3}{5}$

4)

$|5x + 600| = 0 \\ x - 6 = 0 \\ \\ x = - 120 \\ x - 6 = 0 \\ \\ x {}^{1} = - 120 \\ x {}^{2} = 6$

Пошаговое объяснение:

Держи. Я уверен все правильно:) Пж поставь лучший если не трудно:)

Answer 2

To solve each of these equations, we'll need to consider two cases for each absolute value expression: one where the expression inside the absolute value is positive and one where it's negative. Let's go through each equation step by step:

1. |2x - 8| * (x - 18) = 0

Case 1: 2x - 8 is positive (2x - 8 > 0) 2x - 8 = 0 2x = 8 x = 4

Case 2: 2x - 8 is negative (2x - 8 < 0) -(2x - 8) = 0 -2x + 8 = 0 -2x = -8 x = 4

So, in both cases, x = 4.

2. |x - 4| * (2x + 7) = ₽

We can't determine a specific value for x without more information or a specific value for ₽. Please provide the value of ₽ for a solution.

3. |24 + 2x| * (10x - 6) = 0

Case 1: 24 + 2x is positive (24 + 2x > 0) 24 + 2x = 0 2x = -24 x = -12

Case 2: 24 + 2x is negative (24 + 2x < 0) -(24 + 2x) = 0 -24 - 2x = 0 -2x = 24 x = -12

So, in both cases, x = -12.

4. |5x + 600| * (x - 6) = 0

Case 1: 5x + 600 is positive (5x + 600 > 0) 5x + 600 = 0 5x = -600 x = -120

Case 2: 5x + 600 is negative (5x + 600 < 0) -(5x + 600) = 0 -5x - 600 = 0 -5x = 600 x = -120

So, in both cases, x = -120.

In summary, the solutions for these equations are as follows:

1. x = 4
2. x = -12
3. x = -120

For the second equation, we need the value of ₽ to provide a specific solution.