Question

8, 5/6 - 2, 2/6= 3(4)= 3 y + 8-y+4= Розв'яжіть рівняння 9c-6c=33

Answer 1

Ответ:

1)1,05

2) 3×4=12

3) 3y-y+8+4=2y+12=2(y+6)

Answer 2

Let's solve the given equations step by step.

1. First Equation: $8 - \frac{5}{6} - 2 - \frac{2}{6} = 3 \times 4 = 3y + 8 - y + 4$

   Simplifying the left side: $8 - \frac{5}{6} - 2 - \frac{2}{6} = \frac{48 - 5 - 12 - 2}{6} = \frac{29}{6}$

   Simplifying the right side: $3 \times 4 = 12$

   Therefore, we have: $\frac{29}{6} = 12 - 2y + 12$

   $2y = 12 - \frac{29}{6} - 12 = \frac{72 - 29 - 72}{6}$

   $2y = -\frac{29}{6}$

   $y = -\frac{29}{12}$

2. Second Equation: $9c - 6c = 33$

   Simplifying: $3c = 33$

   $c = \frac{33}{3}$

   $c = 11$

So, the solutions are:

• For the first equation: $y = -\frac{29}{12}$
• For the second equation: $c = 11$