Question

(12у+18)•(1,6-0,2y)=0

Answer 1

Ответ:

12y+18=0

12y=0-18

12y=-18

y=-18:12

y=-1,5

1,6-0,2y=0

-0,2y=0-1,6

-0,2y=-1,6

y=-1,6:(0,2)

y=8

Answer 2

To solve the equation (12y + 18) * (1.6 - 0.2y) = 0, you can use the zero-product property, which states that if the product of two factors is equal to zero, then at least one of the factors must be equal to zero.

So, in this case, you have:

1. 12y + 18 = 0
2. 1.6 - 0.2y = 0

Let's solve each equation separately:

1. 12y + 18 = 0

Subtract 18 from both sides:

12y = -18

Now, divide both sides by 12 to isolate y:

y = -18/12

Simplify the fraction:

y = -3/2

2. 1.6 - 0.2y = 0

Add 0.2y to both sides:

1.6 = 0.2y

Now, divide both sides by 0.2 to isolate y:

y = 1.6 / 0.2

Simplify the fraction:

y = 8

So, you have two possible solutions:

1. y = -3/2
2. y = 8

These are the values of y that make the original equation (12y + 18) * (1.6 - 0.2y) = 0 true.