Question

1) 321 + (x + 13) = 450; 3) 204 - (x + 29) = 100;​

Answer 1

Ответ:

321 + (x + 13) = 450; 3) 204 - (x + 29) = 100;

x=5

Answer 2

To solve these equations, you need to isolate the variable "x" on one side of the equation. Let's go through each equation step by step:

1. $321 + (x + 13) = 450$

First, simplify the equation inside the parentheses by adding $x$ and $13$:

$321 + x + 13 = 450$

Now, combine like terms on the left side of the equation:

$334 + x = 450$

Next, subtract $334$ from both sides of the equation to isolate $x$:

$x = 450 - 334$

$x = 116$

So, the solution for $x$ in the first equation is $x = 116$.

2. $204 - (x + 29) = 100$

First, simplify the equation inside the parentheses by subtracting $(x + 29)$ from $204$:

$204 - x - 29 = 100$

Now, combine like terms on the left side of the equation:

$175 - x = 100$

Next, subtract $175$ from both sides of the equation to isolate (x:

$-x = 100 - 175$

$-x = -75$

Finally, multiply both sides of the equation by $-1$ to solve for $x$:

$x = 75$

So, the solution for $x$ in the second equation is $x = 75$.