Question

7(3-2x)=15(1-x) , 7y-1\12 - y+1\4 =2y+5\3

Answer 1

7(3-2x)=15(1-x)
21-14х=15-15х
-14х+15х=15-21
х=-6
7y-1\12 - y+1\4 =2y+5\3
7у-у-2у=5/3+1/12-1/4
4y=18/12
y=18/12*12/48
y=3/1*1/8
y=3/8

Answer 2

Let's solve both equations step by step:

Equation 1: 7(3 - 2x) = 15(1 - x)

First, distribute the constants on the left and right sides of the equation:

7 * 3 - 7 * 2x = 15 * 1 - 15x

Now, simplify both sides of the equation:

21 - 14x = 15 - 15x

Next, add 15x to both sides of the equation to isolate x terms on one side:

21 - 14x + 15x = 15 - 15x + 15x

This simplifies to:

21 + x = 15

Now, subtract 21 from both sides to solve for x:

x = 15 - 21 x = -6

So, the solution to the first equation is x = -6.

Equation 2: 7y - 1/12 - y + 1/4 = 2y + 5/3

Let's simplify this equation step by step:

First, combine like terms on both sides:

(7y - y) - 1/12 + 1/4 = 2y + 5/3

This simplifies to:

6y - 1/12 + 1/4 = 2y + 5/3

Now, let's find a common denominator for the fractions on the left side, which is 12:

(6y - 1/12 + 3/12) = 2y + 5/3

Now, combine the fractions on the left side:

(6y + 2/12) = 2y + 5/3

Now, simplify the fractions on the left side:

(6y + 1/6) = 2y + 5/3

Next, subtract 2y from both sides to isolate the y terms on one side:

6y - 2y + 1/6 = 5/3

This simplifies to:

4y + 1/6 = 5/3

Now, subtract 1/6 from both sides:

4y = 5/3 - 1/6

To subtract these fractions, find a common denominator, which is 6:

4y = (10/6) - (1/6)

Now, subtract the fractions:

4y = 9/6

Simplify the right side by dividing both the numerator and denominator by their greatest common divisor, which is 3:

4y = (9/3) / (6/3) 4y = 3/2

Now, divide both sides by 4 to solve for y:

(4y)/4 = (3/2)/4 y = (3/2) * (1/4) y = 3/8

So, the solution to the second equation is y = 3/8.