Question

3-1/3*[2/3y+1/2]=1/3y+1.5

Answer 1

3-1/3×2/3у-1/3×1/2=1/3у+1 5/10
3- 2/9у-1/6=1/3у+1 1/2
2 5/6-2/9у=1/3у+1 1/2
-2/9у-1/3у=1 1/2-2 5/6
-2/9у-3/9у=3/2-17/6
-5/9у=9/6-17/6
-5/9у=-8/6
-5/9у=-4/3
у=-4/3÷(-5/9)
у=4/3×9/5
у=12/5=2 2/5

Answer 2

Let's solve the equation step by step:

3 - (1/3) * [2/3y + 1/2] = (1/3)y + 1.5

First, let's simplify the expression inside the square brackets:

(1/3) * [2/3y + 1/2] = (2/9)y + (1/6)

Now, we can rewrite the equation:

3 - (2/9)y - (1/6) = (1/3)y + 1.5

To get rid of the fractions, let's multiply both sides of the equation by 18 (the least common multiple of 3 and 9):

18 * [3 - (2/9)y - (1/6)] = 18 * [(1/3)y + 1.5]

Now, distribute the 18 on both sides:

54 - 2y - 3 = 6y + 27

Combine like terms on each side:

51 - 2y = 6y + 27

Now, let's isolate the variable y by moving terms with y to one side and constants to the other:

51 - 27 = 6y + 2y

24 = 8y

Now, divide both sides by 8 to solve for y:

y = 24 / 8 y = 3

So, the solution to the equation is y = 3.