Question

-42+75+(-14)+(-26)+56= 12+(-20)-(-11)-(-6)-10= 3 5/12-(-1 1/3)+(-4 3/8)

Answer 1

1)51
2)-1
3)1,2083
вот и всё

Answer 2

Let's solve each of these arithmetic expressions step by step:

1. $-42 + 75 + (-14) + (-26) + 56$

First, add the positive numbers and negative numbers separately:

$75 + 56 = 131$
$-42 + (-14) + (-26) = -82$

Now add the results:

$131 - 82 = 49$

So, $-42 + 75 + (-14) + (-26) + 56 = 49$.

2. $12 + (-20) - (-11) - (-6) - 10$

Start by resolving the double negatives:

$12 + (-20) + 11 + 6 - 10$

Now add the positive and negative numbers:

$12 + 11 + 6 - 20 - 10 = 19 - 30 = -11$

So, $12 + (-20) - (-11) - (-6) - 10 = -11$.

3. $3 \frac{5}{12} - (-1 \frac{1}{3}) + (-4 \frac{3}{8})$

Start by resolving the double negative and converting mixed fractions to improper fractions:

$3 \frac{5}{12} + 1 \frac{1}{3} - 4 \frac{3}{8}$

$\frac{37}{12} + \frac{4}{3} - \frac{35}{8}$

To add these fractions, you need a common denominator. The least common multiple of 12, 3, and 8 is 24. Convert each fraction to have a denominator of 24:

$\frac{37 \cdot 2}{12 \cdot 2} + \frac{4 \cdot 8}{3 \cdot 8} - \frac{35 \cdot 3}{8 \cdot 3}$

$\frac{74}{24} + \frac{32}{24} - \frac{105}{24}$

Now, add the fractions:

$\frac{74 + 32 - 105}{24}$

$\frac{1}{24}$

So, $3 \frac{5}{12} - (-1 \frac{1}{3}) + (-4 \frac{3}{8}) = \frac{1}{24}$.

In summary:

1. $-42 + 75 + (-14) + (-26) + 56 = 49$.
2. $12 + (-20) - (-11) - (-6) - 10 = -11$.
3. $3 \frac{5}{12} - (-1 \frac{1}{3}) + (-4 \frac{3}{8}) = \frac{1}{24}$.