Question

F(x)=x^4-5x^3+10x^2, x0=2

Answer 1

F(x0) = 16 - 40 + 40 = 16

Answer 2

To find the value of the function $F(x) = x^4 - 5x^3 + 10x^2$ at the point $x_0 = 2$, we simply need to substitute $x_0$ into the function.

$F(2) = 2^4 - 5 \times 2^3 + 10 \times 2^2$

Now, let's calculate the value:

$F(2) = 16 - 5 \times 8 + 10 \times 4$

$F(2) = 16 - 40 + 40$

$F(2) = 16$

So, the value of the function $F(x)$ at $x_0 = 2$ is 16.