Question

8x в квадрате -12+4= 0 уравнение

Answer 1

$8x^{2} -12+4=0 ; x^{2}= \frac{12-4}{8} ; x= \sqrt{1} ; x=+-1$

Answer 2

To solve the quadratic equation 8x^2 - 12x + 4 = 0, we can use the quadratic formula. The quadratic formula is given by:

x = (-b ± √(b^2 - 4ac)) / 2a

Where: a, b, and c are the coefficients of the quadratic equation ax^2 + bx + c = 0.

In our case, the coefficients are: a = 8 b = -12 c = 4

Now, let's plug these values into the quadratic formula to find the solutions for x:

x = (12 ± √((-12)^2 - 4 * 8 * 4)) / 2 * 8

x = (12 ± √(144 - 128)) / 16

x = (12 ± √16) / 16

Now, let's find the two possible values of x:

1. x = (12 + √16) / 16 x = (12 + 4) / 16 x = 16 / 16 x = 1

2. x = (12 - √16) / 16 x = (12 - 4) / 16 x = 8 / 16 x = 1/2

So, the solutions to the equation 8x^2 - 12x + 4 = 0 are x = 1 and x = 1/2.