Question

(4-y)^2-y(y+1) при y= - 1/9 найдите значения выражения

Answer 1

$(4 - y)(4 - y) - y(y + 1) = \\ (4 + \frac{1}{9} )(4 + \frac{1}{9} ) + \frac{1}{9} ( 1 - \frac{1}{9} ) = \\ = 16 + \frac{8}{9} + \frac{1}{81} + \frac{1}{9} - \frac{1}{81} = \\ = 16 + 1 = 17$
Ответ : 17

Answer 2

Решение на фотографии

Answer 3

To find the value of the expression (4-y)^2 - y(y+1) when y = -1/9, simply substitute the value of y into the expression and perform the arithmetic.

Let's do that step-by-step:

Step 1: Substitute y = -1/9 into the expression (4-y)^2 - y(y+1)

(4 - (-1/9))^2 - (-1/9)(-1/9 + 1)

Step 2: Simplify the expression inside the parentheses and the exponent:

(4 + 1/9)^2 - (-1/9)(8/9)

Step 3: Calculate the values inside the parentheses and the exponent:

(37/9)^2 - (-1/9)(8/9)

Step 4: Calculate the square of (37/9):

(1369/81) - (-1/9)(8/9)

Step 5: Simplify the multiplication:

1369/81 + 8/81

Step 6: Find the common denominator and add the fractions:

(1369 + 8)/81

Step 7: Calculate the final value:

1377/81

Step 8: Reduce the fraction, if possible:

17/1

So, the value of the expression (4-y)^2 - y(y+1) when y = -1/9 is 17.