Question

F(x)=2cos 2x+3sin x при x= пи/2, если cos пи=-1, sin пи/2=1 а)-1 б) 5 в)1 г) другой ответ

Answer 1

8y-3(2y-3)=7y-2(5y+8)

8y-6y-9=7y-10y+16

2y-9=-3y+16

2y+3y=16+9

5y=25

y=25:5

y=5

5(2y-9)+6y=4(3y-2)-21

10y-45+6y=12y-8-21

16y-45=12y-29

16y-12y=-29+45

4y=16

y=16:4

y=4

Answer 2

To find the value of F(x) at x = π/2, we need to substitute the given values into the function:

F(x) = 2cos(2x) + 3sin(x)

We are given: cos(π) = -1 sin(π/2) = 1

Now, we'll plug these values into the function and solve for F(π/2):

F(π/2) = 2cos(2 * π/2) + 3sin(π/2) F(π/2) = 2cos(π) + 3sin(π/2) F(π/2) = 2(-1) + 3(1) F(π/2) = -2 + 3 F(π/2) = 1

So, the value of F(π/2) is 1. The correct answer is option "в) 1".