Question

-4x^2- x^2-2 x=0 ПO MO ГИ TE !!! Пж

Answer 1

Твоё получается нижнее

Answer 2

To solve the quadratic equation -4x^2 - x^2 - 2x = 0, we first need to combine like terms:

-4x^2 - x^2 - 2x = (-4 - 1)x^2 - 2x = -5x^2 - 2x = 0

Now, we have a quadratic equation in standard form, ax^2 + bx + c = 0, where a = -5, b = -2, and c = 0.

To solve for x, we can use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / 2a

Substitute the values:

x = (-(-2) ± √((-2)^2 - 4(-5)(0))) / 2(-5) x = (2 ± √(4 + 0)) / -10 x = (2 ± √4) / -10 x = (2 ± 2) / -10

Now, consider the two cases:

Case 1: (2 + 2) / -10 x = 4 / -10 x = -2/5

Case 2: (2 - 2) / -10 x = 0 / -10 x = 0

So, the solutions to the equation are x = -2/5 and x = 0.